Big Idea 1 'Identifying and Correcting Errors'
Practice with identifying and correcting code blocks
alphabet = "abcdefghijklmnopqrstuvwxyz"
alphabetList = []
for i in alphabet:
alphabetList.append(i)
print(alphabetList)
The intended outcome is to determine where the letter is in the alphabet using a while loop
- What is a good test case to check the current outcome? Why?
- Make changes to get the intended outcome.
letter = input("What letter would you like to check?")
i = 0
while i < 26:
if alphabetList[i] == letter:
print("The letter " + letter + " is the " + str(i+1) + " letter in the alphabet")
i += 1
The intended outcome is to determine where the letter is in the alphabet using a for loop
- What is a good test case to check the current outcome? Why?
- Make changes to get the intended outcome.
letter = input("What letter would you like to check?")
count = 0
for i in alphabetList:
if i == letter:
print("The letter " + letter + " is the " + str(count+1) + " letter in the alphabet")
count += 1
This code outputs the even numbers from 0 - 10 using a while loop.
- Analyze this code to determine what can be changed to get the outcome to be odd numbers. (Code block below)
evens = []
i = 0
while i <= 10:
evens.append(i)
i += 2
print(evens)
This code should output the odd numbers from 0 - 10 using a while loop.
odds = []
i = 0
while i <= 9:
odds.append(i+1)
i += 2
print(odds)
This code outputs the even numbers from 0 - 10 using a for loop.
- Analyze this code to determine what can be changed to get the outcome to be odd numbers. (Code block below)
numbers = [0,1,2,3,4,5,6,7,8,9,10]
evens = []
for i in numbers:
if (numbers[i] % 2 == 0):
evens.append(numbers[i])
print(evens)
This code should output the odd numbers from 0 - 10 using a for loop.
numbers = [0,1,2,3,4,5,6,7,8,9,10]
odds = []
for i in numbers:
if (numbers[i] % 2 == 1):
odds.append(numbers[i])
print(odds)
The intended outcome is printing a number between 1 and 100 once, if it is a multiple of 2 or 5
- What values are outputted incorrectly. Why?
- Make changes to get the intended outcome.
numbers = []
newNumbers = []
i = 0
while i < 100:
numbers.append(i)
i += 1
for i in numbers:
if numbers[i] % 5 == 0:
newNumbers.append(numbers[i])
if numbers[i] % 2 == 1:
newNumbers.append(numbers[i])
print(newNumbers)
Challenge
This code segment is at a very early stage of implementation.
- What are some ways to (user) error proof this code?
- The code should be able to calculate the cost of the meal of the user
Hint:
- write a “single” test describing an expectation of the program of the program
- test - input burger, expect output of burger price
- run the test, which should fail because the program lacks that feature
- write “just enough” code, the simplest possible, to make the test pass
Then repeat this process until you get program working like you want it to work.
menu = {"tacos": 9.99,
"fries": 5.99,
"drink": 4.99}
print (menu)
order= input("Hi, What would you like to eat? >>")
if order == "tacos":
print("you ordered tacos, your total is $5.99")
elif order == "fries":
print("you ordered fries, your total is $9.99")
elif order == "drink":
print("you ordered a drink, your total is $4.99")
elif order != "tacos" or "fries" or "drink":
print("That item is not on the menu, try re-order")
Hacks
What errors may arise in your project?
- Some error that may arise in our project is dictionary errors, api errors, and syntax errors. When they input a letter it may not be read correctly and place the letter in the wrong spot or it may not say that a correct letter is included in a word.
What are some test cases that can be used?
- We can test inputting some correct letters and some wrong letters. This will lead to our desired output. If we type in a wrong letter a body part will appear.
Make sure to document any bugs you encounter and how you solved the problem.
- I will document any errors I have and inform my team.
What are “single” tests that you will perform on your project? Or, your part of the project?
- I will first play the game for myself and then I will ask peers to review the game aswell.